If an object is projected vertically upwards with speed , half the escape speed of earth , then the aximum height attained by it is [ R is radius of earth ]

A body is projected vertically upwards with speed sqrt(g R_(e )) from the surface of earth. What is the maximum height attained by the body ? [ R_(e ) is the radius of earth, g is acceleration due to gravity]

A particle is projected vertically with speed V from the surface of the earth . Maximum height attained by the particle , in term of the radius of earth R,V and g is ( V lt escape velocity , g is the acceleration due to gravity on the surface of the earth )

A particle is projected vertically with speed V from the surface of the earth . Maximum height attained by the particle , in term of the radius of earth R,V and g is ( V lt escape velocity , g is the acceleration due to gravity on the surface of the earth )

An object is projected vertically upward from the surface of the earth of mass M with a velocity such that the maximum height reached is eight times the radius R of the earth. Calculate: (i) the initial speed of projection (ii) the speed at half the maximum height.

An object is projected vertically upwards with a velocity u from the surface of the earth. Show that the maximum height reached by the object is h=(u^2R)/(2gR-u^2) where R is the radius of the earth. Calculate escape velocity from it.

A body is projected vertically upwards from the surface of earth with a velocity equal to half of escape speed. What is the maximum height attained by the body ?