A straight line through the point A(3, 4) is such that its intercept between the axes is bisected at A. Its equation is :

Explanation

Let the line be
`(x)/(a) + (y)/(b) = 1`
This line meets the x-axis at A(a,0) and the y-axis at B (0,b).
Therefore, we get
`(3,4)-=((a)/(2),(b)/(2))`
`" or " (a)/(2) = 3,(b)/(2) = 4`
or a = 6 ,b = 8
Therefore, the required line is
`(x)/(6) + (y)/(8) = 1`
or 4x+3y = 24