Find the minimum distance between the curves `y^2=4xa n dx^2+y^2-12 x+31=0`

Find the minimum distance between the curves y^2=4x and x^2+y^2-12 x+31=0

Find the minimum distance between the curves y^2=4x and x^2+y^2-12 x+31=0

Find the minimum distance between the curves y^(2)=4x and x^(2)+y^(2)-12x+31=0

Minimum distance between the curves y^(2)=4x and x^(2)+y^(2)-12x+31=0 is

Minimum distance between the curve y^(2)=4x and x^(2)+y^(2)-12x+31=0 is equal to

Minimum distance between the curve "y^(2)=4x" and " x^(2)+y^(2)-12x+31=0 " ,is equal to 1) sqrt(21) ,2) sqrt(26)-sqrt(5) , 3) sqrt(5) ,4) sqrt(28)-sqrt(5)

Minimum distance between the curves y^(2)=x-1 and x^(2)=y-1 is equal to

The minimum distance between the curves y^(2)-xy-2x^(2)=0 and y^(2)=x-2 is

Find the angle between the curves y^(2)=8x,x^(2)=4y-12