In fig., O is the centre of a circle. The area of sector OAPB is `(5)/(18)` of the area of the circle. Find x.

In given fig, O is the centre of a circle. If the area of the sector OAPB is (5)/(36) times the area of the cicle, then find the value of x.

In given figure, O is the centre of a circle. If the area of the sector OAPB is (5)/(36) times the area of the circle, then find the value of x.

In fig.O is Centre of circle,find x^(@)

In Fig. 2.47, O is the centre of the circle. Shade sectors OAC and OPB.

The area of a sector is one twentieth of the area of the circle. Find the sector angle.

If the area of a sector of a circle is 5/18 of the area of the circle then the sector angle is

The area of a sector of a circle 1/20 the area of the circle Find the sector angle.

If Area of the sector OPRQ =5/(18) of Area of circle. Then the value of x .

The ratio of the area of a sector of a circle to the area of the circle is 1:4. If the area of the circle is 154 cm^2 , the perimeter of the sector is