When 2.74 g of Ba(s) reacts with `O_(2)(g)` at 298K and 1 atm to from Ba(s),11,100J of heat is released . What is `DeltaH_(f)^(@)` for BaO(s)in `Kjxxmol^(-1)`?

The enthalpy change of which reaction corresponds to DeltaH_(f)^(@) "for"Na_(2)CO_(3)(s)298K?

For the reaction, 2A (s) + 2B (g)to C (g) + D(s) at 298K Delta U ^(@) =-10.5KJ and Delta S ^(@)=-44.10 JK^(-1) Calculate Delta G ^(@) for the reaction (in Joules).

For the reaction, 2A (s) + 2B (g)to C (g) + D(s) at 298K Delta U ^(@) =-10.5KJ and Delta S ^(@)=-44.10 JK^(-1) Calculate Delta G ^(@) for the reaction (in Joules).

Calculate DeltaG^(0) for the reaction H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l) at 298K. Given, at 298K DeltaH_(f)^(0) for H_(2)O(l) is -286 kJ *mol^(-1) and the molar entropies (S^(0)) for H_(2)(g),O_(2)(g) and H_(2)O(l) are 130.7, 205.1 and 69.9 J*K^(-1)*mol^(-1) respectively.

If Delta G_(298K) for the reaction 2H_(2(g. 1atm)) + O_(2(g. 1atm)) rarr 2H_(2)O_((g.1atm)) is -240kJ , what will be Delta G_(298K) for the reaction H_(2)O_((g.0.2 atm)) rarr H_(2(g.4atm)) + (1)/(2) O_(2(g.0.26atm))

If Delta G_(298K) for the reaction 2H_(2(g. 1atm)) + O_(2(g. 1atm)) rarr 2H_(2)O_((g.1atm)) is -240kJ , what will be Delta G_(298K) for the reaction H_(2)O_((g.0.2 atm)) rarr H_(2(g.4atm)) + (1)/(2) O_(2(g.0.26atm))

The reaction: NH_(2)CN(s) +(3)/(2)O_(2)(g)rarr N_(2)(g) +CO_(2)(g) +H_(2)O(l) Was carried out in a bomb caloriemeter. The heat released was 743 kJ mol^(-1) . The value of DeltaH_(300K) for this reaction would be