`2cos2 theta=1+sin theta`

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

Assertion: sin2theta=(2tantheta)/(1+tan^2 theta) , Reason: sin^2 theta +cos^2 theta =1,sin2theta=2sinthetacostheta

int_(-pi/2)^(pi/2) cos theta (1+ sin theta)^(2) d theta =

int_(-pi//2)^(pi//2) cos theta (1+sin theta)^(2) d theta=

Solve for theta,2 cos^2 theta+sin theta-1=0,0 le theta le pi/2

Solve the following trigonometric equation : 2 cos^2 theta- 5 sin theta+1=0 .

If cos theta>sin theta>0, then evaluate : int{log((1+sin2 theta)/(1-sin2 theta))^(cos^(2)theta)+log((cos2 theta)/(1+sin2 theta))}d theta

The value of Delta=|(1,sin 3theta, sin^(3)theta),(2cos theta, sin 6 theta, sin^(3)2 theta),(4cos^(2)theta-1,sin 9 theta, sin^(3)3theta)| equal to

The value of Delta=|(1,sin 3theta, sin^(3)theta),(2cos theta, sin 6 theta, sin^(3)2 theta),(4cos^(2)theta-1,sin 9 theta, sin^(3)3theta)| equal to