The filament of an evacuated light bulb has a length 10 cm, diameter 0.2 mm and emissivity 0.2. then the power it radiates at `1727^(@)C` is [`sigma=5.67xx10^(-8)` SI units]

A filament of an evacuated light blue has length 10 cm, diameter 0.2mm and emissivity 0.2. Calculate the power it radiates at 2000 K ( sigma=5.67xx10^-8 J/m^2k^4 )

A spherical black body of 5 cm radius is maintained at a temperature of 327^@C . Then the power radiated will be ( sigma = 5.7 xx 10^(-8) SI unit )

A spherical black body of 5 cm radius is maintained at a temperature of 327^(@)C . Then the power radiated will be (sigma=5.7xx10^(-8)"SI unit")

A 100 watt filament loses all its power by radiation, when it is heated to a temperature 2500 K. If the diameter of the filament is 0.2mm and emissivity of the filament is 0.5, find the length of the filament to ( sigma = 5.67 xx 10^-8 J//m^2sK^4 )

An incandesent light bulb has a tungsten filament that is heated to a temperature 3 xx 106(3)K when an electric current passes through it If the surface area of the filament is approximately 10^(-4)m m^(2) and it has an emissivity of 0.3 the power radiated by the bulb is nearly (sigam = 5.67 xx 10^(-8) W m^(-2) K^(-4)) .

The emissivity of tungsten is approximately 0.35. A tungsten sphere 1 cm in radius is suspended within a large evacuated inclosure whose walls are at 300K. What power input is required to maintain the sphere at a temperature of 3000K? (sigma=5.67xx10^(-8)" in SI unit")

A bulb made of tungsten filament of surface are a 0.5cm^(2) is heated to a temperature 3000 K when operatred at 220V . The emissivity of the filament is e=0.35 and take sigma=5.7xx10^(-8)mks units . Then calculate the wattage of the bulb (in watt)

The surface of a house hold radiator has an emissivity of 0.5 and an area of 1.5 m^(2) . The rate at which the radiation is emitted by then the radiator when its temperature is 47^(@)C will be nearly ( sigma=5.7xx10^(-8) Si units)

A 100 watt filament loses all its power by radiation when it is heated to a temperature of 2500 K. If the diameter of the filament is 0.2 mm and the surface emissivity of the filament is 0.5, find the length of the filament. (Stefan's constant sigma = 5.67 xx10^-8 W/m^2k^4 )