1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar `Ba(OH_(2))` solution. Molecular mass of the acid is:

The pH of 0.25 M Ba(OH)_2 solution is:

1.575 g of a dibasic acid is neutralised by 25 mL 1 M NaOH solution. Hence, molar mass of dibasic acid is -

0.45 g of a dibasic acid is completely neutralised with 100 ml N/10 NaOH . The molecular weight of acid is

0.45 g of a dibasic acid is completely netralised with 100 ml N/10 NaOH . The molecular weight of acid is

1.26 g of a dibasic acid were dissolved in water and the solution made up to 200 mL. 20 mL of this solution were completely neutralised by 10 mL of N/5 NaOH solution. Calculate the equivalent mass and molecular mass of the acid.