A solution of saturated `CaF_2` is found to contain `4.1 xx 10^(-4)` M fluoride ion. Calculate the Ksp of `CaF_2`. Neglect hydrolysis.

A saturated solution of CaF_(2) is found to contain 2 xx 10^(-4) M of F^(-) ions. K_(sp) of CaF_(2) is:

A solution of CaF_(2) is found to contain 4 xx 10^(-4)M of F^(Theta) , K_(sp) of CaF_(2) is

A solution of CaF_(2) is found to contain 4 xx 10^(-4)M of F^(Theta) , K_(sp) of CaF_(2) is

A solution of caF_(2) is found to contain 10^(-4)M F^(Θ) ions. What is the K_(sp) of caF_(2) ?

a. A solution of caF_(2) is found to contain 10^(-4)M F^(Θ) ions. What is the K_(sp) of caF_(2) ? b. A solution of calcium phoshate contains 2 xx 10^(-5)M PO_(4)^(3-) ions. What is K_(sp) of ca_(3)(PO_(4))_(2) ? c. A solution of Ca_(3)(PO_(4))_(2) contains 6 xx 10^(-5)M ca^(2+) ions. What is the K_(sp) of Ca_(3) (PO_(4))_(2) ? d. A solution of Zr_(3)(PO_(4))_(4) constains 8 x 10^(-5) M PO_(4)^(3-) ions. what is the K_(sp) of Zr_(3) (PO_(4))_(4) ? e. A solution of Zr_(3)(PO_(4))_(4) contain 3 xx 10^(-5) M Zr^(4+) ions. What is the K_(sp) of Zr_(3)(PO_(4))_(4) ?

The concentration of Ca^(2+) ions in a saturated CaF_2 solution is 8.4 mg*L^(-1) at 25^(@) C. Calculate the solubility product of CaF_2 at that temperature.