Using vectors: Prove that if a,b,care the lengths of three sides of a triangle then its area `Delta` is given by `Delta= sqrt(s(s-a)(s-b)(s-c))` where 2s=a+b+c

If A is the area and 2s the sum of three sides of a triangle, then

If a,b,c are the sides of a triangle and s=(a+b+c)/(2), then prove that 8(s-a)(s-b)(s-c)<=abc

If bar(a), bar(b), bar(c ) are the sides and s is the semi perimeter of the tirangle ABC then the area of the triangle Delta = sqrt(s(s-a) (s-b) (s-c))

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

If a,b,c are the sides of a triangle and s=(a+b+c)/2 , prove that 8(s-a)(s-b)(s-c)leabc .