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In the figure sin theta=square, tan thet...


In the figure `sin theta=square, tan theta =square`

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Prove cot theta+tan theta=(cosec theta)(sec theta) by completing the following activity: LHS =cot theta+tan theta =(cos theta)/(sin theta)+(square)/(cos theta) =(square +square)/(sin thetaxx co cos theta) =(square)/(sin thetaxx cos theta) =1/(square)xx1/(square) =cosec thetaxx sec theta =RHS :.cot theta+tan theta=cosec thetaxx sec theta