If `sin A=(3)/(4)` and A is not in the first quadrant, then find `(cosA+cos2A)/(tanA+secA)`.

Given tanA=4/3 then find (cosecA)/(cosA-secA)

If sinA=1/3 then cosA. cosecA+tanA.secA=

If secA=-2 and A lies in third quadrant, find the value of (4 cot^(2)A-3sin^(2)A) .

If secA=-2 and A lies in third quadrant, find the value of (4 cot^(2)A-3sin^(2)A) .

If A lies in the first quadrant and 6tanA = 5, then the value (8 sinA -4 cosA)/(cosA + 2 sinA) is : यदि A प्रथम चतुर्थाश में स्थित है तथा 6tanA = 5 है, तो (8 sinA -4 cosA)/(cosA + 2 sinA) का मान क्या होगा ?

If cosA=3/5 , then find the value of (sinA-cosA)/(2tanA)

cosA(secA-cosA)(cotA+tanA)=?

If A is in the fourth quadrant and cos A=(5)/(13) , find the value of (13 sin A+5 secA)/(5tanA+6" cosec"A) .