If `x=a{costheta+logtan""(theta)/(2)}" and "y=asintheta,` then `(dy)/(dx)` is equal to

If x = a{costheta + log tan((theta)/(2))} andy = a sin theta, then (dy)/(dx) is equal to

If x=a(costheta+logtan(theta/2)) and y=a sin theta," show that "(dy)/(dx)=tantheta

If x = a (cos x + log tan theta/2) and y = a sin theta then dy/dx is equal to

x = a(costheta + logtan(theta/2), y = asintheta, find dy/dx.

If x=a(costheta+log"tan"(theta)/(2)) and y=asin theta , then find the value of (dy)/(dx) at theta=(pi)/(4) .

If x=a(cost+1/2logtan'(t)/(2) and y=asint then find (dy)/(dx) at t=pi/4

if x = a(theta-sintheta), y=(1+costheta) , then (dy)/(dx) is equal to