Home
Class 12
MATHS
The perpendicular bisector of a line seg...

The perpendicular bisector of a line segment with end points (1, 2, 6) and `(-3, 6, 2)` passes through `(-6, 2, 4)` and has the equation of the form `(x+6)/(l)=(y-2)/(m)=(z-4)/(n)` (where `l gt0`), then the value of `lmn -(l+m+n)` equals to

Promotional Banner

Similar Questions

Explore conceptually related problems

A line L passes through the point P(5,-6,7) and is parallel to the planes x+y+z=1 and 2x-y-2z=3 .What is the equation of the line L ?

The equations of bisectors of two lines L_(1)&L_(2) are 2x-16y-5=0 and 64x+8y+35=0. lf the line L_(1) passes through (-11,4), the equation of acute angle bisector of L_(1)o*L_(2) is:

A line L passeds through the points (1,1) and (2,0) and another line L' passes through ((1)/(2), 0) and perpendicular to L. Then the area of the triangle formed by the lines L, L' and Y-axis is

A line L passeds through the points (1,1) and (2,0) and another line L' passes through ((1)/(2), 0) and perpendicular to L. Then the area of the triangle formed by the lines L, L' and Y-axis is

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

If (x-1)/(l)=(y-2)/(m)=(z+1)/(n) is the equation of the line through (1,2,-1) and (-1,0,1) then (l,m,n)

If (-2,6) is the image of the point (4,2) with respect to line L=0, then find the equation of line L.