`costheta-cos2theta=sin3theta`

If sintheta-3sin2theta+sin3theta=costheta-3cos2theta+cos3theta , then one of the general value is:

The value of (2(sin2theta+2cos^2theta-1))/(costheta-sintheta-cos3theta+sin3theta) is adot costheta b. sectheta c. cosectheta d. sintheta

The value of (2(sin2theta+2cos^2theta-1))/(costheta-sintheta-cos3theta+sin3theta) is a.\ costheta b. sectheta c. cosectheta d. sintheta

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .

If (sin8theta.costheta-sin6theta.cos3theta)/(cos2theta.costheta-sin3theta.sin4theta)=tan(Ktheta) then: K=... (a) 1 (b)2 (c) 3 (d) none of these

If sintheta+sin2theta+sin3theta=sinalpha and costheta+cos2theta+cos3theta=cosalpha , then theta is equal to

Prove that (sin theta+ sin 2theta + sin 3 theta)/(costheta+cos2theta+cos3theta)=tan 2 theta

(3costheta+cos3theta)/(3sintheta-sin3theta)=

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1