A particle is moving with velocity ` vecv = k( y hat^(i) + x hat(j)) `, where `k` is a constant . The genergal equation for its path is

A particle is moving with a velocity, \vec { v } = K ( y \hat { i } + x \hat { \j } ) , where K is a constant. The general equation for the path is:

The position vector of a particle is given by vec(r ) = k cos omega hat(i) + k sin omega hat(j) = x hat(i) + yhat(j) , where k and omega are constants and t time. Find the angle between the position vector and the velocity vector. Also determine the trajectory of the particle.

A particle moves with a velocity (5 hat(i)+3 hat(j)+6 hat(k)) m//s under the influence of a constant force (5 hat(i)+5 hat(j)+10hat(k))N . The instantaneous power applied to the particle is

At a given instant of time the position vector of a particle moving in a circle with a velocity 3hat i - 4 hat j + 5 hat k is hat i + 9 hat j - 8 hat k . Its angular velocity at that time is:

A particle is moving with speed 6m//s along the direction of vec(A)=2hat(i)+2hat(j)-hat(k) , then its velocity is :

A particle is moving with speed 6m//s along the direction of vec(A)=2hat(i)+2hat(j)-hat(k) , then its velocity is :

A plane mirror is moving with velocity 4 (hat i) + 4 (hat j) + 8 (hat k) . A point object in front of the mirror moves with a velocity 3 (hat i) + 4 (hat j) + 5 (hat k) . Here, hat k is along the normal to the plane mirror and facing towards the object. The velocity of the image is

A plane mirror is moving with velocity 4 (hat i) + 4 (hat j) + 8 (hat k) . A point object in front of the mirror moves with a velocity 3 (hat i) + 4 (hat j) + 5 (hat k) . Here, hat k is along the normal to the plane mirror and facing towards the object. The velocity of the image is