हल कीजिये `tan^(2) theta=1/3`

The period of ( tan theta -(1)/(3) tan^(3) theta ) ((1)/(3) - tan^(2) theta )^(-1), where tan^(2) theta ne (1)/(3) is :

tan theta+(1)/(tan theta)=2 then prove that tan^(2)theta+(1)/(tan^(2)theta)=2

If tan theta+1/(tan theta)=2 , then show that tan^(2)theta+1/(tan^(2)theta)= 0

If tan theta+(1)/(tan theta)=2, find the value of tan^(2)theta+(1)/(tan^(2)theta)

Find, theta =tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=