Family of lines

Suppose the family of lines ax+by+c=0 (where a, b, c are in artihmetic progression) be normal to a family of circles. The radius of the circle of the family which intersects the circle x^(2)+y^(2)-4x-4y-1=0 orthogonally is

A family of lines is given by (1+2 lambda)x+(1-lambda)y+lambda=0 being a parameter.The line belonging to this family at the maximum distance from the point (1,4) is ax+by+c=0, then find the value of (a+b+c)/(16)

33 (d) 11 (c) (b) 3 (a) V10 Given the family of lines, a(2x y 40 b x -2y -3) 0. Among the lines of the family, the number of lines situated at a distance of v 10 from the point M (2,-3)) is (b) 1 (a) 0 (d) co o. Point (0, B) lies on or inside the triangle formed by the lines and 0, x y 2, 1, o Then o can be

Intro, Addition Low, Dot Product, Cross Product, STP, VTP, Vector Equction, 3D, Line, Family of Line

Introduction,Various Form of Lines ,Point and Line,Line and Line ,Family of Line ,Angle Bisector

If a,c,b are in AP the family of line ax+by+c=0 passes through the point.

Consider the family of line (x+y-1)+lamda(2x+3y-5)=0 and (3x+2y-4)+mu(x+2y-6)=0 Equation of a straight line that belongs to both the families is:

Consider the triangle ABC having vertex A(1,1) and its orthocentre is (2,4). Also side AB & BC are members of the family of line, ax + by + c = 0 where a,b,c are in A.P. The vertex C is :