Home
Class 12
PHYSICS
A body of mass 6.28 kg is suspended from...

A body of mass 6.28 kg is suspended from one end of a wire of length 10 m. The radius of the wire is changing uniformly from `19.6xx10^-4m` at one end to `10 xx 10^-4 m` at the order end. Find the change in the length of the wire.
`[Y=2xx10^11N//m^2]`

Promotional Banner

Similar Questions

Explore conceptually related problems

A body of mass 3.14 kg is suspended from one end of a non uniform wire of length 10m, such that the radius of the wire is changing uniformly from 9.8xx10^(-4) m at one end to 5xx10^(-4) m at the other end. Find the change in length of the wire in mm. Young's modulus of the material of the wire is 2xx10^(11)N//m^(2) (mass of wire is negligible)

A body of mass 3.14 kg is suspended from one end of a wire of length 10 m . The radius of cross-section of the wire is changing uniformly from 5xx10^(-4) m at the top (i.e. point of suspension) to 9.8xx10^(-4) m at the bottom . Young's modulus of elasticity is 2xx10^(11) N//m^(2) . The change in length of the wire is

A body of mass 3.14 kg is suspended from one end of a wire of length 10 m . The radius of cross-section of the wire is changing uniformly from 5xx10^(-4) m at the top (i.e. point of suspension) to 9.8xx10^(-4) m at the bottom . Young's modulus of elasticity is 2xx10^(11) N//m^(2) . The change in length of the wire is

A 5 kg wt is suspended from the end of a wire 2.5 m long fixed to a rigid support. The diameter of the wire is 2 mm. If Y = 20 x 10^10 N/m^2 for the material of the wire, find the increase in its length.g = 9.8 m/s^2 .

What mass must suspended from the free end of a steel wire of length 2m and diameter 1mm to stretch it by 1mm ? (Y=2xx10^(11)Nm^(-2))

A body of mass 1 kg is fastened to one end of a steel wire of cross- section area 3 xx 10^(-6)m^(2) and is rotated in horizantal circle of radius 20 cm with a constant speed 2 m//s . Find the elongation of the wire (Y= 2 xx 10^(11) N//m^(2))

When a load of 10 kg is hung from one end of a wire of length 5 m, the wire elongates by 5 mm. IF the young modulus for the material of the wire is 9.8 times 10^10 N.m^-2 , then find the area of cross section of the wire. [g=9.8 m.s^-2 ]

One end of a wire 2 m long and dameter 2 mm is fixed in a celling . A naughty boy of mass 10 kg jumps to catch the free end and stays, there. The chamge is length of wire is (Take r = 10 m//s^(2), Y= 2 xx 10^(11) N//m^(2) )