In `Delta ABC ; (b-c)cot(A/2)+(c-a)cot(B/2)+(a-b)cot(C/2)`

Prove that in any /_\ABC . (b-c)cot(A/2)+(c-a)cot (B/2)+(a-b)cot (C/2)=0

In Delta ABC prove that (b-c)cot(A/2) + (c-a)cot(B/2) + (a-b)cot(C/2) = 0

For any triangle ABC prove that (b-c)cot(A/2)+(c-a)cot(B/2)+(a-b)cot(C/2) =0

In any triangle A B C , prove that: (b-c)cot (A/2)+(c-a)cot (B/2)+(a-b)cot (C/2) =0

In any triangle ABC, prove that: (b-c)cot(A)/(2)+(c-a)cot(B)/(2)+(a-b)cot(C)/(2)=0

In Delta ABC, cot ""(A)/(2) +cot""(B)/(2) + cot""(C)/(2)=

In a Delta ABC, if cot((A)/(2)):cot((B)/(2)):cot((C)/(2))=1:4:15 then the greatest angle is

In any triangle A B C , prove that: (b-c)cot A/2+(c-a)cot B/2+(a-b)cot C/2 =0

In any triangle ABC, prove that, (b-c)cot 'A/2' + (c-a) cot 'B/2' + (a-b) cot 'C/2'=0

In a triangle ABC if cot(A/2)cot(B/2)=c, cot(B/2)cot(C/2)=a and cot(C/2)cot(A/2)=b then 1/(s-a)+1/(s-b)+1/(s-c)=