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If f(x)=3x-5, then f^(-1)(x) is given b...

If `f(x)=3x-5,` then `f^(-1)(x)` is given by `1/((3x-5))` is given by `((x+5))/3` does not exist because `f` is not one-one does not exist because `f` is not onto

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If f(x)=3x-5, then f^(-1)(x) (a) is given by 1/((3x-5)) (b) is given by ((x+5))/3 (c) does not exist because f is not one-one (d) does not exist because f is not onto

If f(x)=3x-5, then f^(-1)(x) is given by (a) (1)/((3x-5)) (b) ((x+5))/(3) (c)does not exist because f is not one-one (d)does not exist because f is not onto

If f(x)=3x-5, then f^(-1)(x) is given by (a) 1/((3x-5)) (b) ((x+5))/3 (c)does not exist because f is not one-one (d)does not exist because f is not onto

If f(x)=3x-5, then f^(-1)(x) is given by (a) 1/((3x-5)) (b) ((x+5))/3 (c)does not exist because f is not one-one (d)does not exist because f is not onto

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If f:R rarr R is given by f(x)=3x-5 then f^(-1)(x)

If f : R to R is given by f(x) = 3x-5, then f^(-1) (x) is