If `f_k(x)=1/k(sin^kx+cos^kx)` then `f_4(x)-f_6 (x)=` (A) `1/12` (B) `5/12` (C) `(-1)/12` (D) `-5/12`

Let f_K(x)""=1/k(s in^k x+cos^k x) where x in R and kgeq1 . Then f_4(x)-f_6(x) equals (1) 1/6 (2) 1/3 (3) 1/4 (4) 1/(12)

kx + 3y = 3, 12 x + k y = 6 .

Let f_(k)(x)=(1)/(k)(sin^(k)x+cos^(k)x) where x in R and k>=1. Then f_(4)(x)-f_(6)(x) equals

Let f(x)={(x^4-5x^2+4)/(|(x-1)(x-2)|)\ \ \ \ ,\ \ \ x!=1,\ 1 6\ \ \ \ \ \ \ \ \ \ \ \ \ ,\ \ \ x=1 ,\ \ \ \ \12 ,\ \ \ \ \ \ \ \ \ x=2 . Then, f(x) is continuous on the set R (b) R-{1} (c) R-{2} (d) R-{1,\ 2}

If f(x)={(kx+2,,x 5) is continuous, then value of k is

f(x)=-(1)/(3)x^(3)+5x^(2)+12

If for f(x) = kx^(2) + 5x + 3, f'(2) = 6 , then k is equal to

Let f(x)=(kx)/(x+1) then the value of k such that f(x) is