The two lines `lx+my=n and llx+m'y=n'` are perpendicular if

The lines lx+my+n=0,mx+ny+l=0 and nx+ly+m=0 are concurrent if (where l!=m!=n)

Show that the lines lx+my+n=0, mx+ny+l=0 and nx+ly+m=0 are concurrent if l+m+n=0

The lines (lx+my)^2-3(mx-ly)^2=0 and lx+my+n=0 forms

The lines (lx+my)^2-3(mx-ly)^2=0 and lx+my+n=0 forms

The lines (lx+my)^2-3(mx-ly)^2=0 and lx+my+n=0 forms

The lines (lx+my)^2-3(mx-ly)^2=0 and lx+my+n=0 forms

If line lx+my+n=0 is perpendicular to one of the lies ax^(2)+2hxy+by^(2)=0 then

If I,m,n are in A.P then the lines represented by lx+my+n=0 are concurrent at the point

Find the equation of the straight line through the point (alpha,beta) and perpendiculasr to the line lx+my+n=0