Magentic moment of `Fe^(a+)(Z= 26 )` is `sqrt 24 BM`. Hence muber of unpaired electron and value lf a respectively are :

Spin magnetic moment of X^(n+) (Z=26) is sqrt(24) B.M. Hence number of unpaired electrons and value of n respectively are:

Spin magnetic moment of X^(n+) (Z=26) is sqrt(24) B.M. Hence number of unpaired electrons and value of n respectively are:

The magnetic moment of M^(x+) (atomic number = 25 is sqrt(15) BM .The number of unpaired electron and the value of x respectively are

Magnetic moment of M^(x+) is sqrt(24)BM . The number of unpaired electrons in M^(x+) is.

The magnetic moment of M^(+) (atomic number = 25 is sqt(15) BM .The number of unpaired electron and the value of x respectivekly are

The magnetic moment of M^(x+) (atomic number of M=25) is sqrt(15)BM . The number of unpaired electrons and the value of x respectively are-

The number of unpaired electrons in Fe^3+ (Z=26) are

Magnetic moment of Mn^(+2) is 5.8 B.M. Hence the number of unpaired electrons presenting the metal ion is