If `x=1+1/(3+1/(3+1/(2...oo)))` then the value of x is

x = 1 + (1)/(3+(1)/(2+(1)/(3+1/(2...oo)))) then the value of x is

x = 1 + (1)/(3+(1)/(2+(1)/(3+1/(2...oo)))) then the value of x

If quad cos^(-1)x<1 and 1+sin(cos^(-1)x)+sin^(2)(cos^(-1)x)+sin^(3)(cos^(-1)x)+...oo=2 then the value of 12x^(2) is

If quad 1(1)/(1-2x+x^(2))=1+b_(1)x+b_(2)x^(2)+b_(3)x^(3)+...oo,|x|<1, then the value of b_(1) is

If lim_(x to oo) [ (x^(3)+1)/(x^(2)+1)-(ax+b)]=2 , then the values of a and b are -

If y=1+(x)/(1!)+(x^(2))/(2!)+(x^(3))/(3!)+(x^(4))/(4!)+...oo, then find the value of (dy)/(dx) .

If y=1+(x)/(1!)+(x^(2))/(2!)+(x^(3))/(3!)+(x^(4))/(4!)+...oo, then find the value of (dy)/(dx) .

If 0 < cos^(-1)x < 1 and 1+sin(cos^(-1)x)+sin^2(cos^(-1)x)+sin^3(cos^(-1)x)....+oo=2, then the value of 12 x^2 is____.

If 0ltcos^(-1)x lt 1 and 1+sin(cos^(-1)x)+sin^(2)(cos^(-1)x)+sin^(3)(cos^(-1)x)+…….oo=2 , then the value of 12x^(2) is

Let f" [1,2] to (-oo,oo) be given by f(x)=(x^(4)+3x^(2)+1)/(x^(2)+1) then find value of in [f_(max)]" in "[-1,2] where [.] is greatest integer function :