यदि `sintheta=(m^(2)+2mn)/(m^(2)+2mn+2n^(2))` हो, तो सिद्ध कीजिए कि
`tantheta=(m^(2)+2mn)/(2m+2n^(2))`.

If sintheta=(m^(2)-n^(2))/(m^(2)+n^(2)) , then tantheta=?

Factorise: m ^(2) - 4 mn + 4n^(2)

Verify that (m + n) ( m ^(2) - mn + n ^(2)) = m ^(3) + n ^(3)

Simplify the following : (m-n)(m^(2)+mn+n^(2))

If tan theta+sin theta=m and tan theta-sin theta=n then m^(2)-n^(2)=4mn(b)m^(2)+n^(2)=4mnm^(2)-n^(2)=m^(2)+n^(2)(d)m^(2)-n^(2)=4sqrt(mn)