The displacement of a harmonic oscillator is given by `x=alpha sin omegat+beta cosomegat`. Then the amplitude of the oscillator is,

The displacement of a harmoniv oscillatore is given by x=alphasinomegat+betacosomegat. What is the amplitude of the oscillation?

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The equation of displacement of a harmonic oscillator is x = 3sin omega t +4 cos omega t amplitude is

The displacement s of a particle at time t is given by s=alpha sin omegat+beta cos omegat then acceleration at time t is

The displacement of a particle executing simple harmonic motion is given by y= A_(0) +A sin omega t+ B cos omega t . Then the amplitude of its oscillation is given by:

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is