A particle oscillates simple harmonic motion with a period of `16 s`. Two second after crossing the equilibrium position its velocity becomes `1 m//s`. The amplitude is

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm. The displacement from the equilibrium position where its energy becomes half-potential and half-kinetic is