2 gm of a metal when dissolved in `HNO_(3)` , gets converted into nitrate salt. The nitrate was then precipitated to form 2.66 gm of metal chloride. Equivalent mass of metal can be :

2 g of a metal when dissolved in nitric acid converted to its nitrate. The nitrate was then precipitated to 2.66 g of the metal chloride. Find the equivalent weight of the metal.

2 g of a metal when dissolved in nitric acid converted to its nitrate. The nitrate was then precipitated to 2.66 g of the metal chloride. Find the equivalent weight of the metal.

x g of metal reacts with chlorine to form y g of metal chloride. Calculate equivalent mass of metal.

1.60 g of a metal were dissolved in HNO_3 to prepare its nitrate. The nitrate was strongly heated when 2.0 g of the metal oxide was obtained. Calculate the equivalent weight of the metal.

X gm of metal gave Y gm of its oxide, so equivalent mass of metal is :

X gm of metal gave Y gm of its oxide, so equivalent mass of metal is :

1.60 g of a metal was dissolved in HNO_3 to prepare its nitrate. The nitrate salt on strong heating gave 2g oxide. The equivalent mass of metal is: