If ` alpha + beta + gamma = 2 theta , " then " cos theta + cos ( theta - alpha ) + cos (theta - beta ) + cos ( theta - gamma ) = `

If alpha + beta + gamma = 2 theta , prove that cos theta + cos(theta- alpha) + cos(theta- beta) + cos(theta -gamma) = 4(cos (alpha/2) cos (beta/2) cos (gamma/2))

If alpha +beta + gamma = 2theta then costheta+ cos(theta-alpha)+cos(theta-beta)+ cos(theta-gamma)

If alpha+beta+gamma= 2theta., then costheta+ cos(theta-alpha)+ cos(theta-beta)+cos(theta-gamma)

If cos 3 theta = alpha cos theta + beta cos ^(3) theta, then (alpha, beta) =

It is given that cos(theta-alpha)=a, cos(theta-beta)=b What is cos(alpha-beta) equal to ?

If alpha and beta are 2 distinct roots of equation a cos theta + b sin theta = C then cos( alpha + beta ) =

If alpha and beta are 2 distinct roots of equation a cos theta + b sin theta = C then cos( alpha + beta ) =