Home
Class 12
PHYSICS
The electric field of light wave is give...

The electric field of light wave is given as `vec(E)=10^(-3)cos((2 pi x)/(5xx10^(-7))-2pi xx 6xx10^(14)t) hat(x) (N)/(C)`. This light falls on a metal plate of work function 2 eV. The stopping potential of the photo-electrons is:
Given, E (in eV) `= (12375)/(lambda ( "in" Å ))`

Promotional Banner

Similar Questions

Explore conceptually related problems

The electric field of light wave is given as vec(E )=10^(-3)cos((2pi x)/(5xx10^(-7))-2pixx6xx10^(14)t)hat(x)(N)/(C ) This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is : Given E (in eV) = (12375)/(lambda("in"Å))

Light of energy 2.0 eV falls on a metal of work function 1.4 eV . The stopping potential is

Light of energy 2.0 eV falls on a metal of work function 1.4 eV . The stopping potential is

Electric field associated with a light wave is given E= E_(0) sin [1.57 xx10^(15)x +6.28 xx10^(15) t] V/m. If this light incident on a surface of work function 2.0 eV the stopping potential will be -

Electric field associated with a light wave is given E= E_(0) sin [1.57 xx10^(15)t +6.28 xx10^(15) t] V/m. If this light incident on a surface of work function 2.0 eV the stopping potential will be -

Electric field associated with a light wave is given E= E_(0) sin [1.57 xx10^(15)t +6.28 xx10^(15) t] V/m. If this light incident on a surface of work function 2.0 eV the stopping potential will be -

The wave function (in SI unit) for a light wave is given as Psi(x,t) = 10^(3) pi(3 xx 10^(6) x - 9 xx 10^(14)t) . The frequency of the wave is equal to