An athlete is given glucose of energy equivalent to 880 kJ. He utilises 50% of this gained energy in the event, in order to avoid storage of energy in the body. The weight of water he would need to perspire is _________ .
(enthalpy of evaporation of water is 44 kJ `mol^-1`)

An athlete is given 100 g of glucose ( C_6H_12O_6 ) of energy equivalent to 1560 kJ. He utilises 50% of this gained energy in the event. In order to avoid the storage of energy in the body, calculate the weight of water he would need to perspire. The enthalpy of evaporation of water is 44 kJ mol^(-1) .

An athelete is given 100 g glucose of energy equivalenet to 1560 kJ. He utilizes 50% of this gained energy in an event. In order to avoid storage of energy in body, calculate the weight of water he need to perspire. Enthalpy of H_(2)O for evaporation is 44 kJ "mole"^(-1) .

An athelete is given 100g of glucose (C_(6)H_(12)O_(6)) of energy equivalent to 1560 kJ . He utilises 50% of this gained enegry in the event. In order to avoid storage of enegry in the body, calculate the weight of water he would need to perspire. The enthalpy of evaporation of water is 441kJ//mol .

An athelete is given 100g of glucose (C_(6)H_(12)O_(6)) of energy equivalent to 1560 kJ . He utilises 50% of this gained enegry in the event. In order to avoid storage of enegry in the body, calculate the weight of water he would need to perspire. The enthalpy of evaporation of water is 441kJ//mol .

An athlete is given 180 g of glucose (C_(6)H_(12)O_(6)) . He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of energy in the body, calculate the masss of water he would need to perspire. Given enthalpy of combustion of glucose is -2800 kJ mol^(-1) and enthalpy of evaporation of water is 44 kJ mol^(-1)