An ionic atom equivalent to hydrogen atom has wavelength equal to `1//4` of the wavelengths of hydrogen lines. The ion will be

The third line of Balmer series of an ion equivalent to hydrogen atom has wavelength of 108.5mm . The ground state energy of an electron of this ion will e

If the shortest wavelength of Lyman series of hydrogen atom is x, then the wavelength of first member of Balmer series of hydrogen atom will be

The first member of the Balmer series of hydrogen atom has wavelength of 6563 A. Calculate the wavelength and frequency of the second member of the same series.

The shortest wavelength of Lyman series of the hydrogen atom is equal to the shortest wavelength of Balmer series of a hydrogen -like atom of atomic number Z. The value of Z is equal to

The shortest wavelength of Lyman series of the hydrogen atom is equal to the shortest wavelength of Balmer series of a hydrogen -like atom of atomic number Z. The value of Z is equal to

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is .........

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion.The atomic number Z of hydrogen like ion is .