Blocks are in contact on a frictionless table. A horizontal force F = 3N is applied to one block as shown. The force exerted by the smaller block `m_(2)` on block `m_(1)` is-

Two blocks of mass m=1 kg and M=2 kg are in contact on a frictionless table. A horizontal force F(=3N) is applied to m. Find the force of contact between the blocks. Will the force of contact remain same if F is applied to M?

Two blocks of mass m = 1 kg and M = 2 kg are in contact on a frictionless table. A horizontal force F(= 3N) is applied to m. The force of contact between the blocks, will be-

Two blocks are in contact on a frictionless table. A horizontal force is applied to the larger block, as shown in Fig. 5-53. (a) If m_(1)=2.3" kg", m_(2)=1.2" kg", and F = 3.2 N, find the magnitude of the force between the two blocks. (b) Show that if a force of the same magnitude F is applied to the smaller block but in the opposite direction, the magnitude of the force between the blocks is 2.1 N, which is not the same value calculated in (a). (c) Explain the difference.

Two blocks of 2 kg and 1kg are in contact on a frictionless table. If a force of 3N is applied on 2kg block, then the force of contact between the two blocks will be

The metal blocks A and B of masses 2 kg and 1 kg , respectively are in contact on a frictionless table A constant horizontal force of 3 N is applied to the block A . Calculate the force of constant between the two blocks . If the same force is applied to the block B then what will be the force of contact ? Can you explain the difference ?

Two blocks are in contact on a frictionless table. A horizontal force is applied to one block as shown in fig. If m_1=10kg and m_2=5kg and F=15N . Find the force of contact between the two bodies.