1.0 L solution is prepared by mixing 61 g benzoic acid `(pK_(a)=4.2)` with 72 g of sodium benzoate and then 300 mL 1.0 M HBr solution was added. The pH of final solution is :

A buffer solution is prepared by mixing 10 mL of 1.0 M acetic acid and 20 mL of 0.5 M sodium acetate and then diluted to 100 mL with distilled water, The pH of the buffer solution is ( pK_(a) of acetic acid is 4.76 )

A buffer solution is prepared by mixing 10ml of 1.0 M acetic acid & 20 ml of 0.5 M sodium acetate and then diluted to 100ml with distilled water. If the pK_(a) of CH_(3)COOH is 4.76 . What is the pH of the buffer solution prepared?

A buffer solution is prepared by mixing 10ml of 1.0 M acetic acid & 20 ml of 0.5 M sodium acetate and then diluted to 100ml with distilled water. If the pK_(a) of CH_(3)COOH is 4.76 . What is the pH of the buffer solution prepared?

Fixed volume of 0.1 M benzoic acid (pK_(a)=4.2) solution is added into 0.2 M sodium benzoate solution and formed a 300 mL, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid :

Fixed volume of 0.1 M benzoic acid (pK_(a)=4.2) solution is added into 0.2 M sodium benzoate solution and formed a 300 mL, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid :

Fixed volume of 0.1 M benzoic acid (pK_(a)=4.2) solution is added into 0.2 M sodium benzoate solution and formed a 300 mL, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid :

Fixed volume of 0.1M benzoic acid (pK_(a) = 4.2) solution is added into 0.2M sodium benzote solution and formed a 300mL , resulting acidic buffer solution. If pH of the resulting solution is 3.9 , then added volume of banzoic acid is

Fixed volume of 0.1M benzoic acid (pK_(a) = 4.2) solution is added into 0.2M sodium benzote solution and formed a 300mL , resulting acidic buffer solution. If pH of the resulting solution is 3.9 , then added volume of banzoic acid is

1 ml of 0.1 N HCl is added to 1 L solution of sodium chloride. The pH of the resulting solution is

A solution was prepared by dissolving 0.63g of nitric acid in 10 L of the solution. Calculate its pH.