[" 42."sin12^(@)sin48^(@)sin54^(@)=],[" a."1/16" b.1/32"]

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sin12^(0)sin48^(@)sin54^(@)=

sin 12^(@)sin 48^(@)sin 54^(@)=

Find sin12^@ sin48^@ sin54^@

sin(12^(@))sin(48^(@))sin(54^(@))= ………..

sin12^(@)sin24^(@)sin48^(@)sin84^(@)=

sin12^@sin24^@sin48^@sin84^@=

sin 12 ^(@) sin 48^(@) sin 54 ^(@) = (1)/(8).

sin12^(@)sin24^(@)sin48^(@)sin84^(@)=?