[" (D) "(cosec A-sin A)(sec A-cos A)=()/(tan A+cos A)],[" .Fint : Singlify IHS and RHS scparately? "]

Prove the following identity,where the angles involved are acute angles for which the expressions are defined.( ix) (csc A-sin A)(sec A-cos A)=(1)/(tan A+cot A)[ Hint : Simplify L.HS and RHS separately]

Prove the following identities, where the angles involved are acute angles for which the expressions are defined. (cosec A -sin A) (sec A - cos A)=1/(tan A + cot A) [Hint :Simplify LHS and RHS separately]

Prove that: (cosec A-sin A)(sec A-cos A)=(1)/(tan A+cot A)

(cosec x-sin x)(sec x-cos x)(tan x+cot x)

Prove that ( "cosec" A - sin A)(sec A- cos A)=(1)/((tan A+ cot A)).

Prove that ( "cosec" A - sin A)(sec A- cos A)=(1)/((tan A+ cot A)).

Prove that : (cosec A-sin A ) (sec A-cos A)=sinA cosA

( cosec A - sin A ) (sec A - cos A ) = ( 1 ) /( tan A + cot A )

Prove that (cosec A - sin A ) (sec A -cos A) = ( 1)/( tan A +cot A)

Prove that (cosec A - sin A ) (sec A -cos A) = ( 1)/( tan A +cot A)