[" The momentum of a photo of energy "1MeV" in "kgm/s" ,will be "],[" (1) "0.33times10^(6)quad " (2) "7times10^(-24)]

The momentum of a photon of frequency 50 xx 10^(17) s^(-1) is nearly

The momentum of a photon of frequency 50 xx 10^(17) s^(-1) is nearly

What will be the angular momentum of a electron,if energy of this electron in H-atom is 1.5eV (in J-sec) (A) 1.05times10^(-34) (B) 2.1times10^(-34) (C) 3.15times10^(-34) (D)-2.1times10^(-34)

Calculate the momentum of a photon of frequency 5 xx 10^(13) Hz .Given, h = 6.6 xx 10^(-34)J.s and c = 3 xx 10^(8) m.s^(-1)

The energy of photons of radiations whose frequency is 6.0times10^(14)s^(-1) is given as "a times10^(-19) s. What is "a"?

The uncertainty in the momentum of an electron is 1.0xx10^(-5)kgms^(-1) . The uncertainty in position will be (h=6.6xx10^(-34)kgm^(2)s^(-1))

The uncertainty in the momentum of an electron is 2.0 × 10^(−5)kgms^(−1) . The uncertainty of its position will be: [h = 6.626 × 10^(−34)kgm^2s^(−1) ]

The uncertainty in the momentum of an electron is 5.0 × 10^(−2)kgms^(−1) . The uncertainty of its position will be: [h = 6.626 × 10^(−34)kgm^2s^(−1) ]