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1+2/2+3/(2^2)+4/(2^3)+... to n terms...

`1+2/2+3/(2^2)+4/(2^3)+...` to n terms

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2+ 3.2 + 4.2^(2) + …... upto n terms =

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If S_(n)=(1.2)/(3!)+(2.2^(2))/(4!)+(3.2^(2))/(5!)+...+ up to n terms, then sum of infinite terms is

If S_(n)=(1.2)/(3!)+(2.2^(2))/(4!)+(3.2^(2))/(5!)+...+ up to n terms, then sum of infinite terms is

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"The sum of the series, 1/ 2.3 ⋅ 2 + 2/ 3.4 ⋅ 2^ 2 + 3/ 4.5 ⋅ 2^ 3 + ... ... . . to n terms is

STATEMENT-1 : If 1^(2) - 2^(n) + 3^(2) …….."to" 21 terms is 231 STATEMENT-2 : If 1^(3) - 2^(3) + 3^(3) - 4^(5) ……….. to 15 terms is 1856 STATEMENT-3 : If 1^(1) + 3^(2) + 5^(2) …….. to 8 terms is 689