If `x^(2)+y^(2)-4x+6y+c=0` represents a circle of radius 5 then c=

If x^(2)+y^2-4x+6y+c=0 represents a circle with radius 6 then c is

If x^(2) +y^(2) -4x + 6y + c = 0 represents a circle with radius 6 then find the value of c.

If 2x^(2)+by^(2)+4x-6y-1=0 represents a circle, then b=

If 2x^2+lambdaxy+2y^2 +(lambda-4)x + 6y-5=0 represents a circle, then its radius is:

If the circle x^(2) + y^(2) + 4x - 6y - c = 0 bissects the circumference of the circle x^(2) + y^(2) - 6x + 4y - 12 = 0 , then c =

If the circle x^(2) + y^(2) + 4x -22y + c = 0 bisects the circumference of the circle x^(2) + y^(2) - 2x + 8y - d = 0 , then c + d =

If the circle x^(2)+y^(2)+4x+22y+c=0 bisects the circumference of the circle x^(2)+y^(2)-2x+8y-d=0 then c+d

If the circle x^(2)+y^(2)+4x+22y+c=0 bisects the circumference of the circle x^(2)+y^(2)-2x+8y-d=0, then (c+d) is equal to