Position of a particle as a function of time is given as `x^2 = at^2 + 2bt + c`, where a, b, c are constants. Acceleration of particle varies with `x^(-n) then value of n is.

The displacement x of a particle at time t moving along a straight line path is given by x^(2) = at^(2) + 2bt + c where a, b and c are constants. The acceleration of the particle varies as

The displacement of a particle is s = (a+bt)^(6) , where a and b are constants. Find acceleration of the particle as a function of time.

The position x of particle moving along x-axis varies with time t as x=Asin(omegat) where A and omega are positive constants. The acceleration a of particle varies with its position (x) as

The displacement (x) of a particle as a function of time (t) is given by x=asin(bt+c) Where a,b and c are constant of motion. Choose the correct statemetns from the following.

Particle 's position as a function of time is given by x=-t^(2)+4t+4 find the maximum value of position coordinate of particle.

A particle moves rectilinearly. Its displacement x at time t is given by x^(2) = at^(2) + b where a and b are constants. Its acceleration at time t is proportional to

Displacement (x) of a particle is related to time (t) as x = at + b t^(2) - c t^(3) where a,b and c are constant of the motion. The velocity of the particle when its acceleration is zero is given by:

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

The displacement of a particle after time t is given by x = (k // b^(2)) (1 - e^(-bi)) . Where b is a constant. What is the acceleration fo the particle ?