Home
Class 11
PHYSICS
A golfer standing on the ground hits a b...

A golfer standing on the ground hits a ball with a velocity of `52 m//s` at an angle `theta` above the horizontal if `tan theta=5/12` find the time for which the ball is at least `15m` above the ground?
`(g=10m//s^(2))`

Promotional Banner

Similar Questions

Explore conceptually related problems

A golfer standing on the ground hits a ball with a velocity of 52 mis at an angle Q above the 5 horizontal if tan theta = 5/12 find the time for which the ball is LB at least 15m above the ground? (g = m//s^(2) )

A golfer standing on level ground hits a ball with a velocity of 52 m s^-1 at an angle theta above the horizontal. If tan theta = 5//12 , then find the time for which then ball is atleast 15 m above the ground (take g = 10 m s^-2) .

A golfer standing on level ground hits a ball with a velocity of 52 m s^-1 at an angle theta above the horizontal. If tan theta = 5//12 , then find the time for which then ball is atleast 15 m above the ground (take g = 10 m s^-2) .

A golfer standing on level ground hits a ball with a velocity of u=50ms^(-1) at an angle theta above the horizontal.If tan theta=(5)/(12) then the time for which the ball is at least 15m above the ground will be take g=10ms^(-2)

A golfer standing on level ground hits a ball with a velocity of u=52m//s at an angle alpha above the horizontal. If tantheta=5//12 , then the time interval for which the ball is at least 15 m above the ground (i.e. between A and B will be :(take g=10m//s^(2) )

A golfer standing on level ground hits a ball with a velocity of u=52m//s at an angle alpha above the horizontal. If tantheta=5//12 , then the time interval for which the ball is at least 15 m above the ground (i.e. between A and B will be :(take g=10m//s^(2) )

A boy throws a ball with a velocity of 15 m/s at an angle of 15° with the horizontal. The distance at which the ball strikes the ground is