If ABCDE is a pentagon, then `bar(AB) + bar(AE) + bar(BC) + bar(DC) + bar(ED) =`

ABCDE is a pentagon then bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(ED)+bar(AC)=

ABCDE is a regular hexagon. i) If bar(AB) + bar(AE)+ bar(BC) + bar(DC) + bar(ED) + bar(AC)=lambdabar(AC) then lambda=

If ABCD is a square, then bar(AB) + 2 bar(BC) + 3 bar(CD) + 4 bar(DA) =

If ABCDEF is a regular hexagon , then bar(AB) + bar(AC) + bar(AE) + bar(AF) =

If PQRST is a pentagon, then bar(PQ) + bar(PR) + bar(PS) - bar(TQ) - bar(TR) - bar(TS) =

ABCDE is a pentagon. If the sum of the vectors bar(AB),bar(AE), bar(BC), bar(DC), bar(ED), bar(AC) is lambda bar(AC) then find the value of lambda .

ABCDEF is a regular hexagon. If bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(ED)+bar(AC)=lambdabar(AC)" then "lambda=