A point moves in a straight line under the retardation `av^(2)`, where `'a'` is a positive constant and `v` is speed. If the initial speed is `u`, the distance covered in `'t'` seconds is `:`

A body moves in a straight line under the retardation a which is given by a=bv^2 . If the initial velocity is 2 m/s, the distance covered in time t=2 seconds is

A particle moves with an initial velocity V_(0) and retardation alpha v , where alpha is a constant and v is the velocity at any time t. total distance covered by the particle is

A particle moves with an initial velocity V_(0) and retardation alpha v , where alpha is a constant and v is the velocity at any time t. total distance covered by the particle is

If a point moves in a straigth line in such a manner that its retardation is porportional to its speed, the distance covered (x) is associated with speed (v) is -

A particle moves along a straight line with a retardations of av^(n+1) , where v is the velocity at time t and a is a positive constant. If at t = 0 the velocity of the particle is u, show that at = (1)/(n)((1)/(v^(n))-(1)/(u^(n))).

A particle is moving along a straight line with uniform retardation of 2ms^(-2) The initial speed of particle is 20m/s .The distance travelled by the particle during the last one second before it stops is

If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is