Light wave enters from medium 1 to medium 2. Its velocity in `2^(nd)` medium is double from `1^(st)`. For total internal reflection the angle of incidence must be greater than

A sound wave travelling with a velocity V in a medium A reaches a point on the interface of medium A and medium B . If the velocity in the medium B be 2 V , then the angle of incidence for total internal reflection of the wave will be greater than:

The speed of light in media M_(1) and M_(2) are 1.5 xx 10^(8) and 2 xx 10^(8) ms^(-1) respectively. A ray travels from medium M_(1) to the medium M_(2) with an angle of incidence theta . The ray suffers total internal reflection. Then the value of the angle of incidence theta is

A light ray is incident on a rarer medium from a denser medium. The velocity of light in rarer medium is double its value in denser medium. For total internal reflection what should be the value of the critical angle?

When a ray of light enters from one medium to another then its velocity in second medium becomes doubled. The maximum value of angle of incidence so that total internal reflection may not take place will be

When a ray of light enter from one medium to another, its velocity is doubled. The critical angle for the ray for two internal reflection will be

A ray of light is refracted from medium 1 to medium 2. Show that the ratio of the sine of the angle of incidence and the sine of the angle of refraction is equal to the ratio of velocity of light in medium 1 and that in medium 2.

A sound waves passes from a medium A to a medium B . The velocity of sound in B is greater than in A . Assume that there is no absorption or reflection at the boundary . As the wave moves across the boundary :

A sound waves passes from a medium A to a medium B . The velocity of sound in B is greater than in A . Assume that there is no absorption or reflection at the boundary . As the wave moves across the boundary :