The function `f(x)=2x^3-15 x^2+36 x+4` is maximum at `x=` (a) 3 (b) 0 (c) 4 (d) 2

The function f(x) = 2x^(3) -15x^(2) + 36x + 4 is maximum at

The function f(x)=2x^(3)-15x^(2)+36x+4 is maximum at x=(a)3(b)0(c)4(d)2

The maximum value of the function 2x^(3)-15x^(2 ) + 36x+4 is attained at a)0 b)3 c)4 d)2

The function f(x)=2x^(3)-15x^(2)+36x+1 is increasing in the interval

If f(x)=1/(4x^2+2x+1) , then its maximum value is 4/3 (b) 2/3 (c) 1 (d) 3/4

The function f(x)= 2x^(3)-15x^(2) +36x + 1 is increasing in the interval-

The function f(x) = 2x^3 -15x^2+36x+6 is stictly decreasing in the interval

If the function f(x)=x^3-12ax^2+36a^2x-4(agt0) attains its maximum and minimum at x=p and x=q respectively, and if 3p=q^2 , then a is equal to

If the function f(x)=x^3-12ax^2+36a^2x-4(agt0) attains its maximum and minimum at x=p and x=q respectively, and if 3p=q^2 , then a is equal to