The vertex of the parabola `y^2 = 8x` is at the centre of a circle and the parabola cuts the circle at the ends of itslatus rectum. Then the equation of the circle is

The vertex of the parabola y^(2)=8x is at the centre of a circle and the parabola cuts the circle at the ends of tslatus rectum.Then the equation of the circle is

The vertex of the parabola (y-1)^2 =8 (x-1) is at the centre of a circle and the parabola cuts that circle at the ends of its latusrectum. Then the equation of that circle is

A circle of radius r,r ne 0 touches the parabola y ^(2) + 12 x =0 at the ertex of the parabola. The centre of the circle lies to the left of the vertex and the circle lies entriely within the parabola. Then the intervals in which, r lies can be

Find the area of the triangle formed by the lines joining the vertex of the parabola x^(2) = -8y to the ends of its latus rectum.

Find the area of the triangle formed by the lines joining the vertex of the parabola x^(2) = 8y to the ends of its latus rectum.

Find the area of the triangle formed by the lines joining the vertex of the parabola x^(2) = 8y to the ends of its latus rectum.

From the focus of parabola y^(2)=8x as centre a circle is described so that a common chord is equidistant from vertex and focus of the parabola.The equation of the circle is

The equation of a circle passing through the vertex and the extremites of the latus rectum of the parabola y ^(2)=8x is

The equation of a circle passing through the vertex and the extremites of the latus rectum of the parabola y ^(2)=8x is