The `M.I.` of a rod about an axis through its center and perpendicular to it is `I_(0)`. The rod is bent in the middle so that the two halves make an angle `theta`. The moment of inertia of the bent rod about the same axis would be

The moment of inertia of a rod about an axis through its centre and perpendicular to it is 1/12ML² (where M is the mass and L is te length of the rod). The rod is bent in the middle so that the two halves make an angle of 60°. the moment of inertia of the bent rod about the same axis would be

The moment of inertia of a rod about an axis through its centre and perpendicular to its length is ML^2//12 (where M is the mass and L is the lenth of the rod).The rod is bent in the middle so that the two halves make an angle 60^@ .The moment of inertia of the bent rod about the same axis would be :

The moment of inertia of a rod about an axis through its centre and perpendicular to it is (1)/(12)ML^(2) (where M is the mass and L, the length of the rod). The rod is bent in the middle so that the two halves make an angle 60^(@) . The moment of inertia of the bent rod about the same axis would be..........

The moment of inertia of a rod about an axis through its centre and perpendicular to it, is (1)/(12)ML^(2) (where, M is the mass and L is length of the rod). The rod is bent in the middle, so that two halves make an angle of 60^(@) . The moment of inertia of the bent rod about the same axis would be

The moment of inertia of a rod about an axis through its centre and perpendicular to it, is (1)/(12)ML^(2) (where, M is the mass and L is length of the rod). The rod is bent in the middle, so that two halves make an angle of 45^(@) . The moment of inertia of the bent rod about the same axis would be

The moment of inertia of a rod about an axis through its centre and perpendicular to it, is (1)/(12)ML^(2) (where, M is the mass and L is length of the rod). The rod is bent in the middle, so that two halves make an angle of 60^(@) . The moment of inertia of the bent rod about the same axis would be