A soap film of surface tension `3 xx 10^(-2)` formed in a rectangular frame can support a straw as shown in Fig. If `g = 10 ms^(-12)`, the mass of the straw is

A soap film of surface tension 3 xx 10^(-2)N//m formed in a rectangular frame can support a straw as shown in Fig. If g = 10 ms^(-2) , the mass of the straw is

A soap film of surface tension 3 xx 10^(-2)N//m formed in a rectangular frame can support a straw as shown in Fig. If g = 10 ms^(-2) , the mass of the straw is

A thin film of liquid is formed in a rectangular frame of wire and a light slider supports a weight of (2.5 * 10^-2)N .The length of slider is 20cm and its weight negligible. The surface tension is liquid is

A thin film of liquid is formed in a rectangular frame of wire and a light slider supports a weight of (2.5 * 10^-2)N .The length of slider is 20cm and its weight negligible. The surface tension is liquid is

A squre wire frame of side 10 cm is dipped in a liquid of surface tension 28 xx 10^(-3) Nm^(-1) On taking out, a membrane is formed. What is the force acting on the surface of wire frame ?

When a 'U' shaped slider of negligible mass is dipped in a soap solution and lifted, a thin film of soap is formed in the frame. It supports a weight of 2.0 xx 10^(-2) N . If the length of the slider is 40 cm, the surface tension of the film of soap is

A film of soap solution is formed in a rectnagular wire frame of length 10 cm and breadth 5 cm . The surface energy of the film , if the surface tension of soap solution is 0.035 N/m is

A soap film is formed on a rectangular frame of length 7 cm dipping in soap solution. The frame hanges from the arm of a balance. An extra weight of 0.38 g is to be placed in the opposite pan to balance the pull on the frame. Calculate the surface tension of the soap solution. "Given" g= 980 "cms"^(-2).