A circle of radius `sqrt8 ` is passing through origin the point (4,0) . If the centre lies on the line y = x , then the equation of the circle is

A circle of radius sqrt8 is passing through origin and the point (4,0). If the centre lies on the line y =x, then the equation of the circle is a) (x -2) ^(2) + (y-2) ^(2) = 8 b) (x + 2) ^(2) + (y +2) ^(2) =8 c) (x -3) ^(2) + (y -3) ^(2) = 8 d) (x -4) ^(2) + (y-4) ^(2) = 8

A circle passes through the points (-3, 4), (1, 0) and its centre lies on the x-axis. Find the equation of the circle.

A circle passes through the points ( 2,3) and ( 4,5) . If its centre lies on the line, y-4x+ 3 =0 , then its radius is equal to :

A circle passes through the points ( 2,3) and ( 4,5) . If its centre lies on the line, y-4x+ 3 =0 , then its radius is equal to :

The equation of the circle with radius 3 units, passing through the point (2, 1) and whose centre lies on the line y + x = 0 can be

The equation of the circle with radius 3 units, passing through the point (2, 1) and whose centre lies on the line y + x = 0 can be

A circle has radius 3 units and its centre lies on the line y = x - 1. Find the equation of the circle if it passes through (7, 3)

A circle passes through(1,-2) and (4,-3) and its.centre lies on the straight line 3x + 4y= 7. Find the equation of the circle.-

A circle has radius 3 units and its centre lies on the line y=x-1. Find the equation of the circle if it passes through (7,3).

A circle has radius 3 units and its centre lies on the line y=x-1. Find the equation of the circle,if it passes through (7,3) .